SOLUTION: can you please check this for me? I have to solve by using the quadratic formula. 5x^2+x+10=0 a=5 b=1 c=10 b^2-4ac=1^2-4*5*10=-199 -199 is less than 0 so no solution is def

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Question 81278: can you please check this for me? I have to solve by using the quadratic formula.
5x^2+x+10=0
a=5
b=1
c=10
b^2-4ac=1^2-4*5*10=-199
-199 is less than 0 so no solution is defined
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
You are correct: since the discriminant is less than zero, you won't have any real solutions.

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -199 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -199 is + or - .

The solution is

Here's your graph:
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