SOLUTION: The area of a rectangular conference room is represented by the equation A = (x2 + 17x + 72) feet2.
If x = 6 feet and the width = (x + 8) feet, what is the perimeter, in feet,
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Question 811419: The area of a rectangular conference room is represented by the equation A = (x2 + 17x + 72) feet2.
If x = 6 feet and the width = (x + 8) feet, what is the perimeter, in feet, of the room?
Answer by Stitch(470) (Show Source): You can put this solution on YOUR website!
The equation for the area of a rectancle is A = L * W.
The equation for the perimeter of a rectangle is P = 2L + 2W.
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Given: X = 6
Given:
Given:
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Since we know that X = 6, we can solve for W.
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Now we can solve for the area by plugging 6 into the equation for X.
Given:
Simplify
Combine like terms.
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Now we can solve for the length.
Divide both sides by 14.
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Now we can use the perimeter equation.
Simplify
The perimeter of the room is 58 feet.
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