SOLUTION: please help me solve this? (x+4)^2=4

Question 81001: please help me solve this?
(x+4)^2=4
Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
QUESTION:
Solve,
(x+4)^2=4

ANSWER:

At first expand the expression using the identity (a+ b)^2 = a^2 + 2ab + b^2 as follows............

==> (x+4)^2=4

==> x^2 + 8x + 16 = 4

subtract 4 from both sides of this expression

==> x^2 + 8x + 16 - 4 = 4 - 4

==> x^2 + 8x + 12 = 0

this is in the form of a quadratic equation. we can solve this equation using quadratic formula.

Comaparing this equation with the stadard equation, ax^2 + bx + c =0, we have,

a = 1, b = 8 and c = 12

then the solution is given by,

==>

==>

==>

==> x = (-8 + 4)/2 or x = ( -8-4)/2

==> x = -4/2 or x = -12/2

==> x = -2 or x = -6

Hence the solution is x = -2 or -6

To check the solution, plugg any of these values in the given equation......then you can see that it satisfy the given equation

Hope you found this explanation useful.

Regards.

Praseena.

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