SOLUTION: can someone check this for me please!please check this for me 2x^2-6x+3=0 2^2+(-6)+3=0 1^2+(-3)+1.5=0 -3/4^2+x=1.5 x=1.5-(-3)/4^2=0.75 (-3/2)^2+(-0.75)=0 (13/2)=sqrt0.75 an

Question 80824: can someone check this for me please!please check this for me
2x^2-6x+3=0
2^2+(-6)+3=0
1^2+(-3)+1.5=0
-3/4^2+x=1.5
x=1.5-(-3)/4^2=0.75
(-3/2)^2+(-0.75)=0
(13/2)=sqrt0.75
and
(-3/2)=-sqrt0.75
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I can't even imagine what you are trying to do.
--------------
Your Problem:
2x^2-6x+3=0
Use the quadratic formula to get:
x=[6+-sqrt(6^2-4*2(3)]/4
x=[6+-sqrt(12)]/4
x=[6+-2sqrt(3)]/4
x=(3+sqrt3)/2 or x=(3-sqrt3)/2
===============
Cheers,
Stan H.

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