SOLUTION: A basketball player takes a shot a a regulation basket, 10 feet off the floor. He releases the ball with an initial upward velocity of 19 feet per second from a height of 7 feet of

Question 80704: A basketball player takes a shot a a regulation basket, 10 feet off the floor. He releases the ball with an initial upward velocity of 19 feet per second from a height of 7 feet off the floor. How long does it take for the ball to pass through the basket? The vertical motion model is: h=-16T^2+vT+s, where h is the height infeet as a function of time, T is the time in motion in seconds, v is the initial velocity in feet per second, and s is the height in feet.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A basketball player takes a shot a a regulation basket, 10 feet off the floor. He releases the ball with an initial upward velocity of 19 feet per second from a height of 7 feet off the floor. How long does it take for the ball to pass through the basket? The vertical motion model is: h=-16T^2+vT+s, where h is the height infeet as a function of time, T is the time in motion in seconds, v is the initial velocity in feet per second, and s is the height in feet.
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h(t) = -16t^2 + 19t + 7
When the ball passes thru the hoop it is 10 ft. above the floor.
so, let h = 10 ft.
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-16t^2+19t+7=10
-16t^2+19t-3=0
Use the Quadratic Formula:
t=[-19+-sqrt(19^2-4*-16*-3]/-32
t=0.1875 or t=2
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The 1st time is when the ball is on the way up.
The 2nd time is when the ball is coming down to 10 ft.
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2nd time is the answer you want.
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Cheers,
Stan H.
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