SOLUTION: A stone is thrown directly upward from a height of 50 feet with an initial velocity of 56 ft/sec. The height of the stone "t" seconds after it has been thrown is given by the formu
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Question 806717: A stone is thrown directly upward from a height of 50 feet with an initial velocity of 56 ft/sec. The height of the stone "t" seconds after it has been thrown is given by the formula s(t)=-16t^2+56t+50. Use the appropriate algebraic formula to determine the time at which the ball reaches its maximum height and find what the maximum height is.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
s(t)=-16t^2+56t+50
parabola
focus | (7/4, 6335/64)=(1.75, 98.9844)
vertex | (7/4, 99)~~(1.75, 99)
semi-axis length | 1/64 = 0.015625
focal parameter | 1/32 = 0.03125
eccentricity | 1
directrix | s = 6337/64
vertex is the high point
98.9844 ft at 1.75 seconds
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