SOLUTION: The product of two numbers is 28. If the second number is one more than twice the first number, what are the two sets of numbers?
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Question 806148: The product of two numbers is 28. If the second number is one more than twice the first number, what are the two sets of numbers?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the numbers be x & y
xy=28
x=28/y
y-2x=1
subxtitute x
y-2(28/y)=1
y^2-56=y
y^2-y-56=0
y^2-8y+7y-56=0
y(y-8)+7(y-8)=0
(y-8)(y+7)=0
y=8 OR -7
xy = 28
x=-7
so y =-4
(-7,-4)
y=8
then x= 28/8
x=3.5
(3.5,8)
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