SOLUTION: Hello, I am trying to solve this problem and need help.
Directions are to solve, apparently there will be 6 answers.
{{{y^6 + 9y^3 + 8 = 0}}}
Thank you!!!
Algebra.Com
Question 80328: Hello, I am trying to solve this problem and need help.
Directions are to solve, apparently there will be 6 answers.
Thank you!!!
Found 2 solutions by checkley75, mathtutor777:
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
y^6+9y^3+8=0
(y^3+8)(y^3+1)=0
y^3+8=0
y^3=-8
y=-2 answer.
y^3+1=0
y^3=-1
y=-1 answer.
Answer by mathtutor777(6) (Show Source): You can put this solution on YOUR website!
y^6 + 9y^3 + 8 = 0
First, notice that y^6 = (y^3)^2. So this is really a quadratic equation where the variable is y^3. We can solve for y^3 by factoring:
(y^3 + 8)(y^3 + 1) = 0
Now, set both sets of parentheses equal to 0 and solve for y^3.
This gives y^3 = -8 or y^3 = -1. All you have to do now is take the cube root of both sides of both equations. You will get y = -2 or -1.
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