SOLUTION: If the discriminat is negative, would this be a true statement? The discriminant is negative, so the quadratic has no real-valued zeroes and therefore no solution.

Question 80192: If the discriminat is negative, would this be a true statement?
The discriminant is negative, so the quadratic has no real-valued zeroes and therefore no solution.
Found 2 solutions by vertciel, stanbon:
Answer by vertciel(183) (Show Source): You can put this solution on YOUR website!
Hello there,
In quadratic equations, if the discriminant (Δ = b^2 - 4ac) is:
Δ > 0 - This quadratic will have 2 roots, otherwise known as x intercepts.
Δ = 0 - This quadratic will have a double root. That is, both roots will be the same, thus, you get the x co-ordinate of the vertex.
Δ < 0 - You will not get a real solution, but a complex solution. If you have not covered complex numbers yet, then just understand that there will be no x-intercepts since the quadratic does not touch the x axis.
Now, if your discriminant is negative, under which of the three cases will negative discriminants fall?
Be sure to write back if you need more help.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
No
it has no Real Number solutions; but it has two complex number solutions.
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Cheers,
Stan H.
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