SOLUTION: Factor each expression:
B. 6(×^2-4×+4)^2+(×^2-4×+4)-1
C.(4j-2)^2-(2+4j)^2
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Question 799809: Factor each expression:
B. 6(×^2-4×+4)^2+(×^2-4×+4)-1
C.(4j-2)^2-(2+4j)^2
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
B.
Given:
(1)
Let
(2) in (1) to get
(3) which factors into
(4)
Now set each factor of (3) equal to zero to get
(5) 3y - 1 = 0 and
(6) 2y + 1 = 0
Now use y of (2) in (5) to get
(7) or
(8) or
(9)
Using the quadratic formula, we can calcculate the two roots of (9) as
(10)
Now use y of (2) in (6) to get
(11) or
(12) or
(13)
Using the quadratic formula, we can calcculate the two roots of (9) as
(14)
Answer to B:
C.
Given:
(15)
This is the difference of two perfect squares which factors into the product of the sum and difference of the perfect square or
(16) or
(17) or
(18)
Answer to C: -32j
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