SOLUTION: 1. A piece of wire of w cm long is bent to form a rectangle. The length of the rectangle is x cm, and its area is 21 cm2.
a. Show that {{{ w=2x+ 42/x }}}
b. Given that the
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Question 799736: 1. A piece of wire of w cm long is bent to form a rectangle. The length of the rectangle is x cm, and its area is 21 cm2.
a. Show that
b. Given that the perimeter of the rectangle is 19 cm, find the breadth of the rectangle.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Area: 
Perimeter: 
Since you are given that A = 21, it must be true that 
. You are also given that the perimeter is 
.
Substituting in the perimeter expression:
\ =\ 2x\ +\ \frac{42}{x})
If 
, then solve 
for 
. Note: "Breadth" is generally taken to mean "width" which is, in turn, generally taken to mean the smaller of the two dimensions of a rectangle. The two solutions of the quadratic equation that results from the perimeter equation are the length and width of the rectangle and you should report the smaller of the two.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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