SOLUTION: Find the vertex of each equation ! PLEASE HELP SOMEONE !!! 1. h(x) = (x + 2)2 � 1 2. h(x) = (x + 1)2 � 2 3. h(x) = (x - 2)2 - 1 4. h(x) = (x

SOLUTION: Find the vertex of each equation ! PLEASE HELP SOMEONE !!! 1. h(x) = (x + 2)2 � 1 2. h(x) = (x + 1)2 � 2 3. h(x) = (x - 2)2 - 1 4. h(x) = (x - 1)2 � 2 5. h(x) =

Question 795063: Find the vertex of each equation ! PLEASE HELP SOMEONE !!!
1. h(x) = (x + 2)2 � 1
2. h(x) = (x + 1)2 � 2
3. h(x) = (x - 2)2 - 1
4. h(x) = (x - 1)2 � 2
5. h(x) = (x + 2)2 + 1
6. h(x) = (x + 1)2 + 2

Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
The vertex is right there, in front of your eyes.
I'll show you how to look for it.
1. is when ,
because then .
For all other values of ,
and .
So (-2,-1), with and is the minimum and the vertex.

2. has a minimum and vertex at (-1,-2), because
when takes the minimum value

3. has a maximum and vertex at (2,-1).

4. has a maximum and vertex at (1,-2)

5. has a maximum and vertex at (-2,1)

6. has a maximum and vertex at (-1,2)

NOTES:
If you had a minus sign in front of that square, as in
the vertex, at (3,4) in this case, would be a maximum, because for and

When they give you the function as
you will have to transform it to the form given above
to find the vertex.

You an write your exponents with a "^" in front, as in
h(x) = (x + 1)^2 + 2 , and everyone will know you mean

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