SOLUTION: Please help with solving this problem--I'm lost. When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t, where v is the initial upwards ve

Question 79393: Please help with solving this problem--I'm lost.
When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t, where v is the initial upwards velocity in feet per second. If v=36 feet per second, find all values of t for which h=19 feet. Do not round any intermediate steps. Round your answers to 2 decimal places.
Thanks so much!!
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t, where v is the initial upwards velocity in feet per second. If v=36 feet per second, find all values of t for which h=19 feet. Do not round any intermediate steps. Round your answers to 2 decimal places.
:
I think the equations would be: -16t^2 + 36t = 19
:
-16t^2 + 36t - 19 = 0
:
Find the value of t using the quadratic formula: a=-16; b=36; c=-19

:
Two solutions:

t = +.85 sec (At 19' on the way up)
and

t = 1.40 sec (At 19' on the way down)
:
Would look like this:

:
Note that it shows about 19 ft at about .85 sec and 1.4 sec
:
Has this helped you find your way?

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