SOLUTION: I need serious help pleasee~!
-6 2/3 x^2 + 1 1/3 x = 2/3
A x = (-1 +- 10i)/3
Bx = (-1 +- 3i)/10
Cx = (1 +- 3i)/-10
Dx = (-1 +- 3i)/-10
E x = (-1 +- 10i)/-3
F x = (
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Question 791361: I need serious help pleasee~!
-6 2/3 x^2 + 1 1/3 x = 2/3
A x = (-1 +- 10i)/3
Bx = (-1 +- 3i)/10
Cx = (1 +- 3i)/-10
Dx = (-1 +- 3i)/-10
E x = (-1 +- 10i)/-3
F x = (2 +- 3i)/6
-57 3/5 x^2 + 3 3/5 x = -39 3/5 x^2 - 7 1/5 x + 14 2/5
A x = {2 +- i[SQRT(75)}/10
Bx = {3 +- i[SQRT(71)]}/-10
Cx = {-3 +- i[SQRT(57)]}/7
Dx = {-3 +- i[SQRT(71)]}/-10
E x = {-2 +- i[SQRT(75)]}/-7
F x = {2 +- i[SQRT(39)]}/14
-6 2/5 x^2 + 7 1/5 x - 3 1/5 = 0
A x = {-2 +- i[SQRT(13)]}/2
Bx = {-6 +- i[SQRT(47)]}/16
Cx = {9 +- i[SQRT(21)]}/-2
Dx = {7 +- i[SQRT(126)]}/-2
E x = {-9 +- i[SQRT(47)]}/-16
F x = {2 +- i[SQRT(126)]}/-6
*
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Not going to do your whole homework assignment for you. One problem per post.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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