SOLUTION: How do I figure out the standard form of a quadratic equation? y = -X^2 +2X + 13 I got -(X-2)^2 + 15 ....but that is wrong..? Help me find out what I am doing wrong? Thanks

Question 789474: How do I figure out the standard form of a quadratic equation?
y = -X^2 +2X + 13
I got -(X-2)^2 + 15 ....but that is wrong..?
Help me find out what I am doing wrong? Thanks!

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y = -X^2 +2X + 13
Note:: That is already in standard form.
-----
Maybe you want it in intercept form::
x^2 -2x = 13-y
-----
x^2 -2x + 1 = 14-y
-----
(x+1)^2 = -(y-14)
===================
Cheers,
Stan H.
RELATED QUESTIONS
Hello, I cannot figure out how to solve the following problem - sorry it's 3 steps! (answered by richwmiller)

What are the solutions of the quadratic equation? 2x^2 � 16x + 32 What I have so far... (answered by ReadingBoosters)

The legs of a right triangle are 4 cm and x cm. The hypotenuse is (2x-1) cm. What is x? I (answered by Alan3354,ewatrrr,stanbon)

The legs of a right triangle are 4 cm and x cm. The hypotenuse is (2x-1) cm. What is x? I (answered by stanbon)

I've tried this a couple different ways, but the answer wasn't right. I know that the... (answered by susanaramya,nerdybill,MathTherapy)

Find the equation of the quadratic function using the given information. The vertex... (answered by josgarithmetic)

Can you please tell me if i got these correct? Im doing a practice test to study for my... (answered by Edwin McCravy,solver91311)

I have a problem with changing this->->y=4x-11 to standard form. There are others, but If (answered by Earlsdon)

I do not want an answer to the following problem. I did the work, and I am not getting... (answered by stanbon)