SOLUTION: It is desired to have an open bin with a square bottom,rectangular sides,and a height of 3m.If the material for the bottom costs $5.40 per square meter and the material for the sid
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Question 783865: It is desired to have an open bin with a square bottom,rectangular sides,and a height of 3m.If the material for the bottom costs $5.40 per square meter and the material for the sides costs $2.40 per square meter and the material for the sides costs $2.40 per square meter,what is the volume of the bin that can be constructed for $63 worth of material?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
One bottom, and four sides.
Let x = length of side of bottom, a square shape.
Let 3 = length of side for dimension of the three-D figure, perpendicular to the square bottom, which is the height of the bin. 3 is how tall the bin.
Area of the bottom of the bin is , and the cost is .
Area for all four sides of the bin is , and the cost is .
Wanted is cost be $63.
Multiply by 10 and divide by 6,
, which is maybe the easiest equivalent of the equation to work with.
Put in more general form:
Directly use general solution to quadratic equation.
Discrim, , which is
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