SOLUTION: If the product is 48. Find the two consecutive factors and write them as an algebraic expression
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Question 773008: If the product is 48. Find the two consecutive factors and write them as an algebraic expression
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
"Consecutive factors"?
n and n+1 as factors?
n(n+1)=48
n^2+n=48
n^2+n-48=0
Check discriminant:
n will be nonwhole, but irrational.
Did you leave something off the problem?
Maybe for some two whole number factors x and y.
These are your only positive possibilities to get product 48:
________This might be what you want, if consecutive EVEN integers.
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