SOLUTION: What is the vertex of f(x)=4x^2-32x+67?

SOLUTION: What is the vertex of f(x)=4x^2-32x+67?

Algebra.Com

Question 771137: What is the vertex of f(x)=4x^2-32x+67?
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!

y=4(4)^2-32*4+67=3
vertex: (4,3)
:)
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