SOLUTION: one number is equal to the square of another .Find the numbers if both are positive and their sum is 1806
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Question 766630: one number is equal to the square of another .Find the numbers if both are positive and their sum is 1806
Found 2 solutions by MathTherapy, Shana-D77:
Answer by MathTherapy(10551) (Show Source): You can put this solution on YOUR website!
one number is equal to the square of another .Find the numbers if both are positive and their sum is 1806
You can do the check!!
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Answer by Shana-D77(132) (Show Source): You can put this solution on YOUR website!
"one number is equal to the square of another": y = x^2
"if both are positive and their sum is 1806": y + x = 1806
with substitution:
x^2 + x = 1806
Set to zero:
x^2 + x - 1806 = 0
Factor:
(x + 43)(x - 42) = 0
Solve:
x = -43, x = 42
Since your teacher said the numbers are positive, x must = 42.
If y = x^2, then:
y = 1764
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