SOLUTION: solve by using the quadratic formula and checking solution x^2-3x+4=0 b^2-4ac=(-3)^2-4*(1)(4)=9-16=-7 x=(-b�√(b^2-4ac))/2a x=(-(-3)�√(-7))/(2(1)) x=1

Question 766326: solve by using the quadratic formula and checking solution

x^2-3x+4=0
b^2-4ac=(-3)^2-4*(1)(4)=9-16=-7
x=(-b�√(b^2-4ac))/2a
x=(-(-3)�√(-7))/(2(1))
x=1/2-(3�i√(-7))
(1/2 x(3�ix〖√7〗^2-3x(1/2 x(3x(3�ix√(7))+4=0
Is this correct?

Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Just be more careful about how you use text to express your expressions.
The work seems good.

OR if you prefer,

OR still further,

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SOLUTION: solve by using the quadratic formula and checking solution x^2-3x+4=0 b^2-4ac=(-3)^2-4*(1)(4)=9-16=-7 x=(-b�&#8730;(b^2-4ac))/2a x=(-(-3)�&#8730;(-7))/(2(1)) x=1

SOLUTION: solve by using the quadratic formula and checking solution x^2-3x+4=0 b^2-4ac=(-3)^2-4*(1)(4)=9-16=-7 x=(-b�√(b^2-4ac))/2a x=(-(-3)�√(-7))/(2(1)) x=1