SOLUTION: Dear Sir/ Madam,
A pleasant day! can you please help me with this algebraic problem, I need to solve it using quadratic formula but I got confused. Your help will mean a lot.
Algebra.Com
Question 766224: Dear Sir/ Madam,
A pleasant day! can you please help me with this algebraic problem, I need to solve it using quadratic formula but I got confused. Your help will mean a lot. Thanks so much! the problem is z^2-(3+2i) z+(1+3i)=0
i=√(-1) where i=square root of negative 1 .
z^2-(3+2i) z+(1+3i)=0
i=√(-1)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
z\ +\ (1\ +\ 3i)\ =\ 0)
where 
, \ \ )
, and )
So
^2\ -\ 4(1)(1\,+\,3i)}}{2(1)})
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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