SOLUTION: how do you solve (3-y)(y+4)=3y-5

Algebra.Com
Question 765432: how do you solve (3-y)(y+4)=3y-5
Answer by tommyt3rd(5050)   (Show Source): You can put this solution on YOUR website!
(3-y)(y+4)=3y-5
3y+12-y^2-4y=3y-5
y^2+4y-17=

then...

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=84 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 2.58257569495584, -6.58257569495584. Here's your graph:




RELATED QUESTIONS

3y^2 + y - 5 = 0 How do you solve... (answered by Fombitz)
How do you solve for y...... (answered by kiru_khandelwal)
How do you solve: y^4(y^2x^3)^2 over (3y^3)^4x^4 Thank you so... (answered by Fombitz)
x=5 + 3y how do you solve this? 10=4x + 2y how do you solve this? y=4-3x... (answered by rfer)
HOW DO YOU SOLVE... (answered by sehar,ehollins1,JimMarshall,Robee16)
How do you solve this using substitution? 2x = y - 4 -3y = x -... (answered by Dionysus10474)
How do you solve y^(-1/3) -3y^(2/3) /y^(-4/3)? No decimals or negative exponents... (answered by stanbon)
How do you solve this equations: For Y 1) x-6= -1/3y 2) x-7/2=0 3) 4x-3/8y=1 4)... (answered by checkley77)