SOLUTION: I need to know what a parabola graph looks like when the parabola will cross the x-axis at 0 and 12. I worked out the problem I just need to know what the graph will look like. I d

Question 763418: I need to know what a parabola graph looks like when the parabola will cross the x-axis at 0 and 12. I worked out the problem I just need to know what the graph will look like. I don't understand that part of it.
My problem was: -25x^2 + 300x = 0
25x^2 - 300x = 0
25x (x - 12) = 0
25x = 0 or x -12 = 0
I just need to know how to graph it and see what it looks like. I believe the parabola will open downward because it has a negative value.
Found 2 solutions by ramkikk66, josmiceli:
Answer by ramkikk66(644) (Show Source): You can put this solution on YOUR website!
Your solution is right. The quadratic has two roots x = 0 and x = 12.
See the graph below (I have divided the eqn by 25 to make -x^2 + 12*x = 0, which has the same 2 roots, to make it fit.) You are right that the graph opens downwards. It has a max value for x = 6.

:)

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Here's the graph:

--------------
One thing to notice right away is it must go through
( 0,0 ) since making will force
--------------
The x-crossings ( the roots ) are at ( 0,0 ) and ( 12,0 )
--------------
The vertex is at when the equation has the form

For your equation:

---------------
So, the vertex is at ( 6,y ) Now find

The vertex is at ( 6,900 )
The vertex is above the x-crossings, so it
must open down.

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