SOLUTION: {{{ x^2+4x+3=0 }}}
s.s {-3,-1}
Algebra.Com
Question 755455:
s.s {-3,-1}
Found 3 solutions by stanbon, solver91311, GETASEW:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^2+4x+3=0
-----
(x+3)(x+1) = 0
x = -3 or x = -1
================
cheers,
Stan H.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
What a lovely little quadratic equation. What did you want to do with it?
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
Answer by GETASEW(1) (Show Source): You can put this solution on YOUR website!
s.s {-3,-1}
RELATED QUESTIONS
1/3(s-2)=s+4 (answered by AnlytcPhil)
1/3(s-2)=s+4
(answered by HyperBrain)
1/3(s-2)=... (answered by Fombitz)
2[s + 3(s... (answered by stanbon)
3(s+1)-(s-2)=22s solve for... (answered by vidhyak)
Let r(x)=x^2-3 and s(x)=x^3-6. Find... (answered by jim_thompson5910)
5. Determine the behavior of {{{f(x)=(2x^3-4x^2-16x)/(x^3-4x)}}}
Domain :
x –... (answered by jim_thompson5910)
3/5 - 1/2... (answered by HyperBrain)
Given p(x) = x^3+5x^2+4x/3(x+1)(x^2−7x+12),
find:
(a) X-intercept(s)
(b) Y-intercept
(answered by greenestamps)
Given p(x) = x^3+5x^2+4x/3(x+1)(x^2−7x+12),
find:
(a) X-intercept(s)
(b) Y-intercept
(answered by solver91311)
