SOLUTION: The width and the length of a rectangle are consecutive even integers. If the width is decreased by 3 inches, then the area of the resulting rectangle is 24 square inches. What is

Question 753277: The width and the length of a rectangle are consecutive even integers. If the width is decreased by 3 inches, then the area of the resulting rectangle is 24 square inches. What is the area of the original rectangle?
12 in^2
48 in^2
96 in^2
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
EDIT: MISREAD "DECREASED". NOW GIVING PROPER RESULT

w for width and y for length
and

Then is used and the area becomes 24 square inches.

or .

Taking the positive value for n,
original figure, w=6 and length=8.
Original area is square inches.

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

The width and the length of a rectangle are consecutive even integers. If the width is decreased by 3 inches, then the area of the resulting rectangle is 24 square inches. What is the area of the original rectangle?
12 in^2
48 in^2
96 in^2

Let the width be the smaller integer of W
Then length = W + 2

If width is decreased by 3, it becomes: W - 3
Therefore, new width, times original length, equals given area, OR

(W - 3)(W + 2) = 24

(W + 5)(W - 6) = 0

W, or width = - 5(ignore), or 6

Length, therefore = 8 (6 + 2)

Area of original rectangle = 6 * 8, or

You can do the check!!

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