SOLUTION: Please help me solve this question. Show that the real solution of the equation ax2+bx+c=0 are the negative of the real solution of the equation ax2-bx+c=0. Assume that b2-4ac &

Question 750837: Please help me solve this question.
Show that the real solution of the equation ax2+bx+c=0 are the negative of the real solution of the equation ax2-bx+c=0. Assume that b2-4ac ≥ 0.
Thank you
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Show that the real solution of the equation ax2+bx+c=0 are the negative of the real solution of the equation ax2-bx+c=0. Assume that b2-4ac ≥ 0.
----
Use the Quadratic Formula:
ax^2 + bx + c = 0
has solutions: x = [-b+-sqrt(b^2-4ac)]/(2a)
-------
ax^2-bx + c = 0
has solutions: x = [b +- sqrt(b^2-4ac)]/(2a)
-------
[-b+-sqrt(b^2-4ac)]/2a ? [b +- sqrt(b^2-4ac)]/(2a)
-----
-b/(2a) ? b/(2a)
----
-b/(2a) is the negative of b/(2a)
====================================
Cheers,
Stan H.
RELATED QUESTIONS
hi please help me with this question: i think it's under quadratic equation im not sure. (answered by Edwin McCravy)

17. Suppose the real numbers a, b, and c are such that the graph of y = ax2 + bx + c is... (answered by greenestamps)

I have a question for you and I hope that you can help me out with it. The question is; (answered by stanbon)

Help me I'm lost PLEASE Thanks!!!!!!! When using the quadratic formula to solve a... (answered by Nate)

I'M HAVING A REALLY HARD TIME TRYING TO FIGURE THIS OUT. PLEASE HELP. When using the... (answered by stanbon)

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real (answered by MathLover1,math_tutor2020)

Please help me find values of c so that the equation has 2 real number solution, one-real (answered by stanbon)

Somebody please help. The graph has to be a real life situation with numbers to make it,... (answered by stanbon)

Here is my problem. I have state the problem, as it has been put to us and just below... (answered by stanbon)