SOLUTION: I am having a lot of trouble figuring this question out: F(x)= -2(x-3)^2+8 , what is the axis of symmetry and the vertex?

Question 750610: I am having a lot of trouble figuring this question out: F(x)= -2(x-3)^2+8 , what is the axis of symmetry and the vertex?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You can read that information directly from the function, since it is written in standard form. The vertex occurs on the x coordinate x=3. Since the vertex occurs on the symmetry axis, this axis is then also x=3.

If the same size and shape parabola was positioned with vertex on the origin, the equation would be . The graph of your given equation has been offset from this by 3 units to the right and 8 units up; which means the vertex is (3,8).

Summary: Axis of symmetry is x=3, and vertex is (3,8).
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