SOLUTION: y-5=1/3(x+2)^2 (Thank - you)
Algebra.Com
Question 75015This question is from textbook Algebra 1
: y-5=1/3(x+2)^2 (Thank - you)
This question is from textbook Algebra 1
Answer by Alwayscheerful(414) (Show Source): You can put this solution on YOUR website!
From your graph equation, you know the vertex of your parabola.
(-2,5) - vertex
And since the "a" value of the equation is positive, you know that your graph will open up.
To get more points, plug in a point for "x" and you'll get a "y" value.
Graph:
Hope this helps!
RELATED QUESTIONS
Expand the logarithm:
{{{log(((4x^3)/(y^2(x-1)^5)))^(3/2)}}}
Thank... (answered by Hawksfan)
y=(-2/3 * x) +3
thank... (answered by MathLover1)
Please help me solve this equation? Thank you
y=3x-3... (answered by TimothyLamb)
how to solve the x- and y- and asymptotes of these rational functions?... (answered by josgarithmetic)
Please solve using the elimination method
y = (2/3)x - 1
y = -x + 4... (answered by ikleyn,Edwin McCravy)
2x + y - 8 = 0
y = x + 2/3
thank... (answered by jim_thompson5910)
{{{ 1/y + 1/(y+2) = 1/3 }}}
Thank... (answered by Theo)
Simplify the following expression:
((x^4*y^(-2/3))/(x^(5/3)*y^(-2/7))^(-4/7) *... (answered by CubeyThePenguin)
Please solve the equation using the elimination method.
y = (1/2)x - 3
(answered by Alan3354,MathLover1)