SOLUTION: Solve for x; 7(3x+11) = 9(3-6x)

Question 73390: Solve for x;
7(3x+11) = 9(3-6x)
Found 2 solutions by Cintchr, bucky:
Answer by Cintchr(481) (Show Source): You can put this solution on YOUR website!

Start by distributing the 7 and the 9 across their respective quantities.

since the 21x is the smaller x value, subtract it from both sides of the equation.

Add 54 to both sides

divide by 6

Yes, it is okay to have a fraction.
Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
Given:
.
7(3x+11) = 9(3-6x)
.
Solve for x
.
First, on the left side multiply the 7 by each of the terms in the parentheses to get:
.
21x + 77 = 9(3 - 6x)
.
Now on the right side multiply 9 times each of the terms in the parentheses to get:
.
21x + 77 = 27 - 54x
.
Now the object is to get all the terms with x on the right side and all the terms that
are just numbers onto the right side.
.
Begin by adding 54x to both sides of the equation. On the right side this cancels
the - 54x. The equation then becomes:
.
75x + 77 = 27
.
Now subtract 77 from both sides to get rid of the + 77 on the left side. When you do
this subtraction the equation becomes
.
75x = -50
.
Finally solve for x by dividing both sides by the multiplier of x which is 75.
.
x = -50/75 = -2/3
.
So the answer to this problem is x = -2/3
.
Hope that this gives you a little insight into the procedures that can be used to solve
equations.
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