SOLUTION: An object is thrown upward from the top of a 96-foot building with an initial velocity of 80 per second. The height h of the object after t is given by the quadratic equation h=16t

Question 731857: An object is thrown upward from the top of a 96-foot building with an initial velocity of 80 per second. The height h of the object after t is given by the quadratic equation h=16t+80t+96
When will the object hit the ground at when the time is how many seconds?
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The equation should be:

The object will hit the ground when
, so

Divide both sides by

Using the quadratic equation:

( can't use the (+) square root, gives negative t )

The object hits the ground in 6 sec
Here's the plot:

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
An object is thrown upward from the top of a 96-foot building with an initial velocity of 80 per second. The height h of the object after t is given by the quadratic equation h=16t+80t+96
When will the object hit the ground at when the time is how many seconds?
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Using your equation, it will never hit the ground.
Use h(t) = -16t^2 + 80t + 96
Notice the first term is negative, and it's t^2.
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Use h(t) = -16t^2 + 80t + 96
It hits the ground when h(t) = 0
Use h(t) = -16t^2 + 80t + 96 = 0
Solve for t
Ignore the negative value of t.

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