Questions on Algebra: Quadratic Equation answered by real tutors!

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Question 72887This question is from textbook precalculus
: This question is from textbook precalculus

Answer by rahman(247) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-8x%2B3=0
x%5E2-8x=-3
x%5E2-8x%2B16=-3%2B16
x%5E2-8x%2B16=13
%28x-4%29%5E2=13
We can write the last equation like this:
%28x-4%29=sqrt%2813%29
x=4%2Bsqrt%2813%29
or
%28x-4%29=-sqrt%2813%29
x=4-sqrt%2813%29
So, solutions for this quadratic equations are:
x=4%2Bsqrt%2813%29 or x=4-sqrt%2813%29
OK