SOLUTION: The height of a projectile, over time, launched from an initial height of 50 feet can be modeled by the quadratic function, h(x) = -16t2 + 96t + 50, where h(x) is the height of the

Question 725361: The height of a projectile, over time, launched from an initial height of 50 feet can be modeled by the quadratic function, h(x) = -16t2 + 96t + 50, where h(x) is the height of the projectile and t is time, in seconds. If the maximum height reached by the projectile is 344 feet, how long does it take for the projectile to reach its maximum height?
Thanks!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The height of a projectile, over time, launched from an initial height of 50 feet can be modeled by the quadratic function, h(x) = -16t2 + 96t + 50, where h(x) is the height of the projectile and t is time, in seconds. If the maximum height reached by the projectile is 344 feet, how long does it take for the projectile to reach its maximum height?
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max height is the vertex of the parabola, t = -b/2a
Why do you think it's 344 feet?
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PS Use ^ (Shift 6) for exponents.
h(x) = -16t^2 + 96t + 50
PPS Should be h(t)

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