SOLUTION: Find the vertex for y=3(x-5)squared+2

Question 72240This question is from textbook Algebra 1
: Find the vertex for y=3(x-5)squared+2 This question is from textbook Algebra 1

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
In the general equation of a quadratic
Represents a quadratic in "vertex form", in other words the vertex is (h,k). The constant h is the horizontal shift of the vertex and k is the vertical shift of the vertex. For instance if you have it looks like this
The graph of
Where the vertex is at (0,0). If you want to shift the graph up or down, you simply add or subtract the appropriate units. For instance, to shift 3 units up, just add 3.
The graph of (note: h=0 k=3)
For this problem, the shifted units are given to you and all you have to do is find the vertex. If the vertex started at (0,0) and we shifted 2 units up and 5 units to the right then the vertex would be (5,2).
The vertex is the lowest point on the graph

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