SOLUTION: how do i "rewrite this function in the form {{{y=(x-h)^2+k}}} by completing the square. find the vertex of the graph." the function is {{{y=x^2-6x+13}}}. so far i have {{{y=x^2-6x

Question 7168: how do i "rewrite this function in the form by completing the square. find the vertex of the graph." the function is . so far i have which means . but the answer key i have says that the answer is and i don't know how to get the four or how to find the vertex after that. thank you!
Answer by sabanasir(22) (Show Source): You can put this solution on YOUR website!
well to tell u the good news... ur solution is right :) u are confused about getting (x-3)^2 +13??? nooooooo :) when u do x^2 -6x +9 + 13 -9 its right... later u get : (x-3)^2 + 4 because u shall subtract 9 from 13 and u get 4.. ur solution is correct
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