SOLUTION: Hi, I need help on solving extraneous equations. (square root)3x=(squareroot)x+6 (squareroot)3x+2-(SR)2x+7=0 (SR)2x+6-(SR)x-1=2 thank you!

Question 711991: Hi, I need help on solving extraneous equations.
(square root)3x=(squareroot)x+6
(squareroot)3x+2-(SR)2x+7=0
(SR)2x+6-(SR)x-1=2
thank you!
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
There are a few problems with what you posted:

Every equation you posted is ambiguous. None of them make clear what is inside the square root. For example, the first equation could be any of the following:

You have parentheses around the words "square root". Putting parentheses around the radicand (the expression within a radical is called a radicand) is much more important.
I don't think "extraneous equations" is a meaningful phrase. Solving square root equations like these can result in what are called "extraneous solutions".

Please re-post your question using parentheses to make the equations unambiguous.
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