SOLUTION: Fine the real or imaginary solutions of each equation by factoring
{{{X^4-8x^2=-16}}}
Can you also explain how to get this? I don't understand this lesson.
Algebra.Com
Question 708364: Fine the real or imaginary solutions of each equation by factoring
Can you also explain how to get this? I don't understand this lesson.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Add 16 to both sides
x^4 - 8x^2 + 16 = 0
Can be factored to
(x^2 - 4)(x^2 - 4) = 0
then we have
x^2 = 4
x = +/-
two solutions
x = +2
x = -2
:
Graphically
RELATED QUESTIONS
how to find the real or imaginary solutions of each equation by factoring... (answered by jsmallt9)
x^4+2x^3=10x^2
Find the real or imaginary solutions of each equation by factoring.
(answered by Fombitz)
I need to find all the imaginary solutions of the equation by factoring.
x^4+14x^2-32=0
(answered by richard1234)
Find the real or imaginary solutions of each equation by factoring.... (answered by josmiceli)
find the real or imaginary solutions of each equation by factoring.
64x^3=-8
(answered by ankor@dixie-net.com)
Find the real or imaginary solution of each equation by factoring. 125x^3-27=0. I am not... (answered by robertb)
I need to find all real solutions to this equation:
4x^-4 -16x^-2+4 = 0
This is how (answered by stanbon)
Find the real or imaginary solution of each equation by factoring... (answered by robertb)
Find the real or imaginary solution of each equation by factoring.
1: X^3 + 2x^2 + 5x... (answered by stanbon)