SOLUTION: Can someone please help me with this question:) y=-x^2-2x+2 a)Find the y-intercept...I set x to zero and got (0,2) b)Find the x-intercept (use quadratic formula) Please help:)

Question 704148: Can someone please help me with this question:)
y=-x^2-2x+2
a)Find the y-intercept...I set x to zero and got (0,2)
b)Find the x-intercept (use quadratic formula) Please help:)
c)The coordinates of the vertex (no clue)
d)the coordinates of the image of the point corresponding to the y-intercept reflected in the axis of symmetry (really no clue...please help)
Thank you!
Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!
y intercept=========(0,2)
x intercept=========(-1+√3,0),,,,(-1-√3,0)
vertex==============(-1,3)
axis of sym=========x=-1
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