SOLUTION: Solve by completing the square: 2x^2-8x+1=0

Question 701554: Solve by completing the square:
2x^2-8x+1=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve by completing the square:
2x^2-8x+1=0
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x^2 - 4x + ? = -1/2 + ?
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x^2 -4x + 4 = (-1/2) + 4
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(x-2)^2 = 7/2
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x-2 = sqrt(14)/2 or x-2 = -sqrt(14)/2
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x = 2 + (1/2)sqrt(14) or x = 2 - (1/2(sqrt(14)
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Cheers,
Stan H.
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