SOLUTION: (x-5)squared+12=0 how do I get it to the layout to pull the a b and c's out
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Question 699771: (x-5)squared+12=0 how do I get it to the layout to pull the a b and c's out
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(x-5)squared+12=0 how do I get it to the layout to pull the a b and c's out
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(x-5)^2 + 12 = 0
x^2 - 10x + 25 + 12 = 0
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x^2 -10x + 37 = 0
a = 1
b = -10
c = 37
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Cheers,
Stan H.
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