SOLUTION: A rocket is launched from atop a 54-foot cliff with an initial velocity of 119 feet per second. The height of the rocket t seconds after launch is given by the equation h = –16t2

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Question 698152: A rocket is launched from atop a 54-foot cliff with an initial velocity of 119 feet per second. The height of the rocket t seconds after launch is given by the equation h = –16t2 + 119t + 54. Graph the equation to find out how long after the rocket is launched it will hit the ground. Estimate your answer to the nearest hundredth of a second.
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Here's the graph of the equation:

The x-axis is in seconds and the y-axis is feet
If you plug in and then or
see how close you can get to ( hits the ground )

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