SOLUTION: what types of roots does {{{x^2-6x+10=0}}} have?
my work:
a=1
b=-6
c=10
4ac=40
{{{(6+ or - sqrt(36-40))/2}}}
{{{(6+ or - sqrt(-4))/2}}}
{{{(6+ or - i sqrt(4)
Algebra.Com
Question 697487: what types of roots does have?
my work:
a=1
b=-6
c=10
4ac=40
=2
cancel the 2's out and simplify the 6. final answer:
3+ or - i
I know I found the roots. Because of the i does this mean the roots are irrational?
Answer by Positive_EV(69) (Show Source): You can put this solution on YOUR website!
You can use the discriminant to determine the nature of the roots: the discriminant is the part of the quadratic formula under the square root sign; that is, . If the discriminant is positive, there are two real roots. If it is zero, there is a single double root. If it is negative, there are two imaginary roots.
Here, a = 1, b = -6 c = 10, so .
The discriminant is negative, so the equation has two imaginary roots.
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