SOLUTION: Trying to solve Y=-2X^2+BX+5 Assume max value of X=2 Find B
I'm having problem expressing the problem in the Y=A(X-H)^2+K form. The first step of getting it to Y=-2(X-2)^2+K is
Algebra.Com
Question 697093: Trying to solve Y=-2X^2+BX+5 Assume max value of X=2 Find B
I'm having problem expressing the problem in the Y=A(X-H)^2+K form. The first step of getting it to Y=-2(X-2)^2+K is where I'm having trouble. I can solve the problem once it is expressed in the form. I just don't know how to change one form to the other. I'm trying to brush up so I can help my daughter on her SAT practice tests. Thank you very much for any assistance you might provide.
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Trying to solve Y=-2X^2+BX+5 Assume max value of X=2 Find B
.
If the "max value" is achieved when x=2 then
x=2 is also the "axis of symmetry"
.
"axis of symmetry" formula:
x = -b/(2a)
(THIS, you have to remember--it is derived from the quadratic formula)
plugging in the given values:
2 = -b/(2*(-2))
2 = -b/(-4)
2 = b/4
8 = b
RELATED QUESTIONS
Find the vertex, line of symmentry, and the max/min value of f(x)=1/5(x+2)^2+2, is the... (answered by josmiceli)
Trying to find max y-value of the graph... (answered by nyc_function)
A parabola of the form y=ax^2+bx+c has a maximum value of y=3. The y-coordinate of the... (answered by josgarithmetic)
I am having a hard time grasping the concept of functions. My problem I am trying to... (answered by Theo)
How do you complete this function equation f(x)=-2x^2+8x-5. I need to find the vertex h,k (answered by nerdybill)
I am having a problem trying to understand how to find zeros of a function if the problem (answered by Edwin McCravy)
8. Let f(x)=x^2 - 4x + 5.
a. Find the equation of the axis of symmetry of the graph of... (answered by josgarithmetic)
I am supposed to find the maximum value of this equation and am not having any
luck... (answered by Fombitz)
I am having a very difficult time trying to reach the solution to this problem.
I am to (answered by Alan3354,Mathtut)