SOLUTION: A man jumps off a diving board into a pool. The equation h(t)=16T^2 + 40 gives the height,in feet, the man is above the pool t seconds after he jumps. a) how high above the pool

Question 696420: A man jumps off a diving board into a pool. The equation h(t)=16T^2 + 40 gives the height,in feet, the man is above the pool t seconds after he jumps.
a) how high above the pool is the diver after the first second?

b) how high is the diving board?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A man jumps off a diving board into a pool. The equation h(t)=16T^2 + 40 gives the height,in feet, the man is above the pool t seconds after he jumps.
a) how high above the pool is the diver after the first second?
------------
h(t) = 16t^2 + 40
h(1) = 16 + 40 = 56 ft at 1 second
h(5) = 16*25 + 40 = 440 ft at 5 seconds
Do you see a problem with that?
------------
Use
h(t) = -16t^2 + 40
Find h(1)
====================
b) 40 feet

RELATED QUESTIONS
a diver jumps from a diving board 24' above a pool. After t seconds, the diver's height h (answered by ankor@dixie-net.com)

You are jumping off the 12-foot diving board at the manicipal pool. You bounce up at 6... (answered by josmiceli)

a child at a swimming pool jumps off a 12 foot platform into the pool. the child's height (answered by stanbon)

lauren dove into a swimming pool from a 15-foot-high diving board with an intitial upward (answered by ankor@dixie-net.com)

a man jumps off a cliff into water, given the function h(t) = -16t^2+16t+480 where t =... (answered by richard1234,robertb)

lauren dove into a swimming pool from 15 foot high diving board with an initial velocity... (answered by ankor@dixie-net.com)

You are jumping off the 12-foot diving board at the municipal pool. You bounce up at 6... (answered by Alan3354,ikleyn)

Nicks height above the water t seconds after diving from a diving board into a pool can... (answered by ikleyn)

In a pool at a water park, a dolphin jumps out of the water traveling at 20 feet per... (answered by ankor@dixie-net.com)