SOLUTION: Find the vertex of the parabola fx=x^2-6x-2

SOLUTION: Find the vertex of the parabola fx=x^2-6x-2

Algebra.Com

Question 691625: Find the vertex of the parabola
fx=x^2-6x-2
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
fx=x^2-6x-2
you could "complete the square":
fx=(x^2-6x)-2
fx=(x^2-6x+9)-2-9
fx=(x^2-6x+9)-11
fx=(x-3)^2+(-11)
so, vertex is at (3, -11)

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