What is asked in the problem?

Find the lenght and the width of the rectangle to the nearest thousandth.



Given:

Lenght of a rectangle is 3cm more than 2 times its width.

the area of the rectangle is 99 cm^2.



Representation:

Let     x = width of the rectangle

   2x + 3 = length of the rectangle



Write and equation: 

Remember that the Area of the rectangle = Length times the width



 A = (2x + 3)(x)

99 = 2x^2 + 3x

 0 = 2x^2 + 3x - 99



Factor : Use Quadratic Formula

    ax^2 + bx + c = 0, a = 2, b = 3, c= -99



       

        

        

        

       



x = 6.325   and     x = -7.825



no lenght or width that is negative so disregard x = -7.825



width of the rectangle = 6.325 cm   



lenght = 2x + 3 

       = 2(6.325) + 3 

       = 12.65 + 3

       = 15.65 cm





 

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