SOLUTION: On this problem, my instructor asks that we use the Pythagoreans Theorem. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what

Question 68720: On this problem, my instructor asks that we use the Pythagoreans Theorem.
The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the
rectangle?
I have come up with L = 2.44 cm and W = 1.44 cm. Is this correct???
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
I DID NOT COME UP WITH THE SAME ANSWER AS YOU BUT WE ARE FAIRLY CLOSE. MAYBE YOU CAN CHECK BOTH OUR SOLUTIONS----PTAYLOR

In a right triangle, the Pythagorean Theorem states where c is the hypotenuse and a and b are the respective sides.
Let x= width of rectangle
Then x+1=length of rectangle
We are told that the diagonal or{or hypotenuse of the triangle) is 4 cm. So or equation to solve is:
clear parens
subtract 16 from both sides
quadratic in standard form
Using the quadratic formula:

cm -----------------------------width
------------------------length
I think that we can discount the negative value for x

Hope this helps----ptaylor

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