SOLUTION: if the roots of a quadratic equation are (-2+sqrt 6) and (-2-sqrt 6), what is the equation in ax^2+bx+c=0 form?

Question 683336: if the roots of a quadratic equation are (-2+sqrt 6) and (-2-sqrt 6), what is the equation in ax^2+bx+c=0 form?
Found 3 solutions by solver91311, fcabanski, Onmyoji.S:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

If is a root of then is a factor of

So, multiply

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it

Answer by fcabanski(1391)   (Show Source): You can put this solution on YOUR website!
If the roots of the equation were 3 and 5, the factors would be x-3 and x-5 and the equation would be the product of the factors = (x-3)(x-5) = x^2 -8x +15.

Subtract the roots from x to show the factors which are

x-(-2+sqrt(6)) and x - (-2-sqrt(6)) = x+2-sqrt(6) and x+2+sqrt(6). To find the equation multiply those factors together (multiply each term of the second factor by each term of the first factor).

Hope the solution helped. Sometimes you need more than a solution. Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.)

Answer by Onmyoji.S(32)   (Show Source): You can put this solution on YOUR website!
if the roots of a quadratic equation are (-2+sqrt 6) and (-2-sqrt 6), what is the equation in ax^2+bx+c=0 form?
It would be：
(-2+sqrt 6)(-2-sqrt 6）
=4+2sqrt6-2sqrt6-（sqrt6）�
=4-（sqrt6）�
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