SOLUTION: seven years ago varun's age was five times the square of swati's age. three years hence swati's age will be two fifth of varun's age.find their present ages

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Question 682089: seven years ago varun's age was five times the square of swati's age. three years hence swati's age will be two fifth of varun's age.find their present ages
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
seven years ago varun's age was five times the square of swati's age. three years hence swati's age will be two fifth of varun's age.find their present ages
**
let x=swati's present age
7 yrs ago
x-7=swati's age
5(x-7)^2=5(x^2-14x+49)=varun's age
..
3 yrs hence or 4 yrs ago
x-4=swati's age
5(x^2-14x+49)+3=varun's age
swati's age will be two fifth of varun's age
x-4=2/5*5(x^2-14x+49)
x-4=2(x^2-14x+49)
x-4=2x^2-28x+98
2x^2-29x+102=0
(2x-12)(x-8.5)=0
x=6(reject) swati wasn't born 7 yrs ago
x=8.5 (swati's present age)
5(x-7)^2+7=5(1.5)^2+7=18.25 (varun's present age)

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