SOLUTION: I had a problem I was working on with the quadratic equation rule.
{{{x^2+4x+2=0}}}
Eventually I worked the problem down to {{{x= -2 +or- radical 8}}}
The answer I'm suppo
Algebra.Com
Question 68138: I had a problem I was working on with the quadratic equation rule.
Eventually I worked the problem down to
The answer I'm suppose to get from there is
I don't see how this is possible.
Found 2 solutions by stanbon, funmath:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^2+4x+2=0
a=1, b=4, c=2
x=[-4+-sqrt(4^2-4*2]/2
x=[-4+-sqrt8]/2
x=[-4+-2sqrt2]/2
Dividing by "2" you get:
x=[-2+-sqrt2]
Cheers,
Stan H.
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
I had a problem I was working on with the quadratic equation rule.
This is how you solve it by completing the square.
:
If you were supposed to solve it using the quadratic formula:
a=1, b=4 and c=2
Either way you eventually get there.
Happy Calculating!!!!
RELATED QUESTIONS
I need help completing the square for this problem.
16x^2-16x-5=0
So far I have... (answered by Msgenes)
Please help. Solve the following 15x^4-28x^2+5=0. I know that eventually I have to use... (answered by jim_thompson5910,stanbon,solver91311)
Hi, I was working on the problem x^2+2x-15=0 and when I simplified, I got to x^3=7.5. I... (answered by josgarithmetic,MathTherapy)
Doing a quadratic equation problem, i cam across a problem. the equation i got was... (answered by JimboP1977,solver91311)
Can I please reieve help on this problem, with an explanantion of the steps so I cab... (answered by solver91311)
I am working on a quadratic equation. A=3, B=6, C=-4. I have worked the problem out to... (answered by nerdybill)
Hi,
I've been trying to solve a word problem but can't figure out how to do it. I've... (answered by ikleyn)
This is for an exam. I need some help on Solving a quadratic equation with imaginary... (answered by stanbon)
The problem I am working on is :
3(x + 2) – 4x = 3
The way I was working it out... (answered by Cromlix)