SOLUTION: Please help me solve this word problem using the position equation. I have solved the first part but cannot seem to get the second part! A C-141 Starlifter flying at 25,000 fee

Question 680163: Please help me solve this word problem using the position equation. I have solved the first part but cannot seem to get the second part!
A C-141 Starlifter flying at 25,000 feet over level terrain drops a 500-pound supply package.
(a) How long will it take until the supply package strikes the ground?
This is what I have come up with:
s=-16t^2+v0t+s0
Since we don't know the velocity, plug in 0 for v0t.
s=-16t^2+0+25,000
0=-16t^2+25,000
16t^2=25,000
t^2=25,000/16
square root of t^2=square root of 25,000/16
t approximately = 39.5 seconds
Now, here's the part I can't seem to figure out.
(b) The plane is flying at 500 miles per hour. How far will the supply package travel horizontally during it's descent?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Please help me solve this word problem using the position equation. I have solved the first part but cannot seem to get the second part!
A C-141 Starlifter flying at 25,000 feet over level terrain drops a 500-pound supply package.
(a) How long will it take until the supply package strikes the ground?
This is what I have come up with:
s=-16t^2+v0t+s0
Since we don't know the velocity, plug in 0 for v0t.
s=-16t^2+0+25,000
0=-16t^2+25,000
16t^2=25,000
t^2=25,000/16
square root of t^2=square root of 25,000/16
t approximately = 39.5 seconds
Now, here's the part I can't seem to figure out.
(b) The plane is flying at 500 miles per hour. How far will the supply package travel horizontally during it's descent?
------------
500 mi/hr * 39.5 sec * 1 hr/3600 sec = 5.486 miles
-----------
BTW, that's called "air mail"

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